From: Jay Link (jlink@interlink-bbs.com)
Date: Sun 04 Apr 1999 - 16:31:51 IDT
> I have run into a problem in that I can't get my virtual screen to > display on the physical - this makes it rather difficult to see what's > going on :) You forgot to gl_setcontextvga(35) . (you had vgavirtual, but you need vga, too). That will fix your gl_freecontext() problems, too. -J #include <stdio.h> #include <stdlib.h> #include <vgagl.h> #include <vga.h> main() { GraphicsContext *virtualscreen; GraphicsContext *physicalscreen; vga_init(); /*** create virtual screen ***/ gl_setcontextvgavirtual(35); /* G800x600x16M32 */ virtualscreen=gl_allocatecontext(); gl_getcontext(virtualscreen); /*** create physical screen ***/ vga_setmode(35); /* fix below */ gl_setcontextvga(35); /* G800x600x16M32 */ physicalscreen=gl_allocatecontext(); gl_getcontext(physicalscreen); gl_setcontext(virtualscreen); /* draw something here using gl_setpixelrgb() */ gl_copyscreen(physicalscreen); /*** the documentation appears to be wrong here in that */ /*** gl_copyscreen(&physicalscreen) is suggested yet this */ /*** causes a compilation error for me */ while(getchar() != 'x'); /*** at this stage, I should have something visible and be */ /*** waiting for an 'x' input to terminate the programme */ /*** but in fact I am left looking at the same blank screen */ /*** that I started with :( */ vga_setmode(TEXT); gl_freecontext(virtualscreen); /* gl_freecontext(physicalscreen);*/ /*** the commented out line above causes a segmentation fault */ /*** as discussed in my last post */ return (0); }
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